Question

calculate the period of oscillation of a simple pendulum of length 1.8with bob of mass 2.2kg​

Answer 1

Answer:-

• Length=1.8m
• Acceleration due to gravity=10m/s

We know that

$\boxed{\sf T=2\pi Lg}$

$\\ \qquad\quad\sf\longmapsto 2\times \dfrac{22}{7}\times 1.8\times 10$

$\\ \qquad\quad\sf\longmapsto \dfrac{44}{7}\times 18$

$\\ \qquad\quad\sf\longmapsto \dfrac{792}{7}$

$\\ \qquad\quad\sf\longmapsto T=113.1$

$\\ \qquad\quad\sf\longmapsto T=113(Approx)$

Answer 2

Explanation:

Length=1.8m

Acceleration due to gravity=10m/s

We know that

\boxed{\sf T=2\pi Lg}

T=2πLg

\begin{gathered}\\ \qquad\quad\sf\longmapsto 2\times \dfrac{22}{7}\times 1.8\times 10\end{gathered}

⟼2×

7

22

×1.8×10

\begin{gathered}\\ \qquad\quad\sf\longmapsto \dfrac{44}{7}\times 18\end{gathered}

⟼

7

44

×18

\begin{gathered}\\ \qquad\quad\sf\longmapsto \dfrac{792}{7}\end{gathered}

⟼

7

792

\begin{gathered}\\ \qquad\quad\sf\longmapsto T=113.1\end{gathered}

⟼T=113.1

\begin{gathered}\\ \qquad\quad\sf\longmapsto T=113(Approx)\end{gathered}

⟼T=113(Approx)