Calculate the period of revolution of a satellite revolving at a distance of 20 Km above the surface of the
earth (Radius of earth=6400 Km and acceleration due to gravity of earth =10 m/s2
)?
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(1) The value of gravitational acceleration g = 10 ms^-2 . (2) Radius of earth RE = 6400 km. Take pi ... An artificial satellite circle the Earth in a circular orbit at a location where the acceleration due to gravity is 9.00m/s2. Determine the orbital period of the satellite.
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Top answer:
Radius of earth RE = 6400 km = 6.4 × 10^6 mTime period of revolution
Explanation:
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