Question

calculate the period of revolution of satellite revolving at a distance of 20 km above the surface of the earth?​

Answer 1

Answer:

Orbital velocity,

4v

0

=

R

e

+h

GM

e

6380+2620

(6.67×10

−11

)(6×10

24

)

=6.67km/sec

Timeperiodofrevolution,

T=2π

v

0

(R

e

+h)

=

6.67×10

3

2×3.14×(6380+2620)

=8474sec=2.35hours