calculate the pH and poh of a household ammonia solution that cantain 2.5 moles of nh3 per liter of a solution
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Explanation:
From the pH, pOH = 2.5, therefore [OH-] is 3.2 x 10-3 M (convert pH to pOH, -antilog gives [OH-]).
Therefore, [NH4+] = [OH-]=3.2 x 10-3 M.
Kb = [NH4+][OH-]/[NH3] = 1.8 x 10-5
= (3.2 x 10-3)2/x - 3.2 x 10-3 Assume x >> 3.2 x 10-3
x = 0.57 M = [NH3], 0.57 is >> 3.2 x 10-3
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