Question

calculate the pH and poh of a household ammonia solution that cantain 2.5 moles of nh3 per liter of a solution​

Answer 1

Answer:

Explanation:

From the pH, pOH = 2.5, therefore [OH-] is 3.2 x 10-3 M (convert pH to pOH, -antilog gives [OH-]).

Therefore, [NH4+] = [OH-]=3.2 x 10-3 M.

Kb = [NH4+][OH-]/[NH3] = 1.8 x 10-5

= (3.2 x 10-3)2/x - 3.2 x 10-3 Assume x >> 3.2 x 10-3

x = 0.57 M = [NH3], 0.57 is >> 3.2 x 10-3