Question

calculate the ph of 0.001 M solution of H3PO4 Ka =7.5 ×10^-3​

Answer 1

Answer:

Correct option is

A

[H

+

]=[H

2

PO

4

−

]=0.024 M

According to ostwald dilution law-

H

=

=

K

a

×C

H

+

=

7.5×10

−3

×.1

=.024M

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Answer 2

Answer:

In a solution 0.1 M H

3

PO

4

acid, concentration of H

2

PO

4

−

is :

[Use : K

a

1

=10

−3

, K

a

2

=10

−7

and K

a

3

=10

−12