Question

Calculate the pH of 0.001M NaOH.Assuming complete dissociation of base

Answer 1

Answer:

11

Explanation:

NaOH will dissociate into Na+ and OH -

pOH = -log( conc.[OH-] )

= -log( 10^-3 )

= 3

pH = 14 - pOH = 14 - 3 = 11

Answer 2

The pH of the solution is 11

Explanation:

We are given:

Molarity of NaOH = 0.001 M

This compound dissociates into 1 mole of sodium ions and 1 mole of hydroxide ions

To calculate the pH of the solution, we need to determine pOH of the solution. To calculate pOH of the solution, we use the equation:

$pOH=-\log[OH^-]$

We are given:

$[OH^-]=0.001M$

Putting values in above equation, we get:

$pOH=-\log(0.001)\\\\pOH=3$

To calculate pH of the solution, we use the equation:

$pH+pOH=14\\\\pH=14-3=11$

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