Question

calculate the ph of 0.001N h2so4 solution​

Answer 1

Answer:

-log[10^-3]

3log10.......log10=1

3×1=3

Answer 2

Explanation:

N= nf x molarity

Molarity =0.001/2

Concentration of h+ ions= molarity *2 as h2so4 have 2 ionisable hydogens

Ph=-log[10]{concentration}

Ph=3