calculate the pH of 0.001N HCl and 0.01N NaOH salution
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10.0 (2) What is the pH of a 0.0001 M NaOH solution? SOLUTION: Strong base so, pOH = -log[NaOH] = -log(0.0004)=-log(1x10-4)=4.0 pH = 14.0-pOH = 14.0 – 4.0 = 10.0 (makes sense since we expect basic solution).
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