Calculate the PH of 0.002 moles of barium hydroxide solution assuming complete dissassociation.
Answers
Answered by
1
Answer:Calculate the pH of 0.02 m Ba(OH)_2 aqueous solution assuming Ba(OH)_2 as a strong electrolyte.
Explanation:Ba(OH2)→Ba2++2OH-
∴[OH-]=2[Ba(OH)2]
=2×0.02=0.04M.
∴pOH=-log[OH-]
=1.398-1.40.
∴pH=14-1.4=12.6.
Similar questions