calculate the pH of 0.0025 NaOH solution
Answers
Answered by
0
Answer:
11.4
Explanation:
This is the procedure :
NaOH is a strong electrolytes and thus its complete dissociation will produce a solution O.1 M (10-2 M) in OH-. By neglecting [OH] arising from water dissociation (10-7 M)
[H+][OH-] = [H+][OH-]) = 10-14
from which [H+] = 10-13 and pH = - log (10-13) = 13
Alternatively we can calculate pOH = - log [OH-]= - log [10-1] = 1 and remembering that pH + pOH = 14 we get pH = 14 - 1 = 13.
Now place the value and solve
Answered by
1
Answer:
11.39
Explanation:
pOH = -log ( OH-)
= - log ( 2.5* 10^(-3))
= -(log2.5 + log 10^(-3)
= -( log2.5 -3log10)
=- ( log2.5 -3 )
= -(0.39 - 3)
= 2.61
pH + pOH = 14
pH = 14 - 2.61
pH = 11.39
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