Calculate the ph of 0.005 M ba(OH)2
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Answer:
pH=12
Explanation:
pH is the measure of acidity or alkalinity of a substance.
pH is defined as the negative logarithm of hydrogen ion concentration and pOH is defined as the negative logarithm of hydroxide ion concentration.
Ba(OH)_2\rightarrow Ba^{2+}+2OH^-Ba(OH)2
→Ba 2+
+2OH
As 1 mole of Ba(OH)_2Ba(OH)
2
gives 2 moles of OH^-OH
−
ions.
0.005 moles will give=\frac{2}{1}\times 0.005=0.01
1
2
×0.005=0.01 moles of OH^-OH
−
ions.
pOH=-log[OH^-]pOH=−log[OH
−
]
pOH=-log[0.01]=2pOH=−log[0.01]=2
pH = 14 - pOH= 14 - 2= 12.
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