Question

Calculate the ph of 0.005 M ba(OH)2​

Answer 1

Answer:

pH=12

Explanation:

pH is the measure of acidity or alkalinity of a substance.

pH is defined as the negative logarithm of hydrogen ion concentration and pOH is defined as the negative logarithm of hydroxide ion concentration.

Ba(OH)_2\rightarrow Ba^{2+}+2OH^-Ba(OH)2

→Ba 2+

+2OH

As 1 mole of Ba(OH)_2Ba(OH)

2

gives 2 moles of OH^-OH

−

ions.

0.005 moles will give=\frac{2}{1}\times 0.005=0.01

1

2

×0.005=0.01 moles of OH^-OH

−

ions.

pOH=-log[OH^-]pOH=−log[OH

−

]

pOH=-log[0.01]=2pOH=−log[0.01]=2

pH = 14 - pOH= 14 - 2= 12.