Calculate the pH of 0.006M NaOH solution.
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Answer:
11.78
Explanation:
pOH = -log(OH-)
= -log ( 6 x 10 -³)
= 3-log6 = 3- 0.3 - 0.48
= 2.22
pH = 14 - 2.22
= 11.78
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