calculate the pH of 0.01 M CH3COOH if it is 5% dissociated
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based upon the formula
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pH of acetic acid will be - 3.3
Molarity of acetic acid is - 0.01 M
Hence, concentration of hydrogen ions is - 0.01 M.
Dissociation constant of acid is given as 5%, which is equivalent to 0.05.
Hence, total hydrogen ion concentration will be - 0.05*0.01
= 5*10^-4.
pH is negative log of hydrogen ions.
pH = -log (5*10^-4)
pH = 3.3
Hence, pH of given acetic acid solution will be - 3.3.
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