Calculate the pH of 0.01 M inNaOH solution
Answers
Answered by
2
ph should be 12..
according to poh = -log (oh-)
ph = 14 - poh
where poh = -log 10^-2
poh =2
so ph = 14 -2 = 12..
please mark this answer as brainliest and follow me too
javedsaif0:
please mark this answer as brainliest and follow me too
Answered by
1
Hεγα βυδδγ !! ❤️❤️
answer.... ⬇️⬇️
pOH = -log[OH-]
= -log[10^-2]
= -(-2)
= 2
14 = pOH + pH
pH = 14-2
pH = 12
Hope helps !! ❤️❤️
hello can u tell me how do you write these special words??
Similar questions