Question

Calculate the ph of 0.01 m solution of monobasic if it is degree of dissociation 4.2%

Answer 1

Answer:

Dissociation reaction of acetic acid is

so, concentration of [H^+] =

where C is concentration of acetic acid and is degree of dissociation.

so, [H^+] = 0.01 × 0.001 = 10^-5

so, pH = -log[H^+] = -log(10^-5) = 5

hence, pH is 7