Question

Calculate the ph of 0.01 m solution of nh4cl the dissociation constant k for hcl is equal to 6.2 into 10 to the power minus 10 and kb for nh3 is equal to 1.6 into 10 to the power minus 5

Answer 1

pH = 9.2 ○ Explaination - # Given - C = 0.01 M ka(HCN) = 6.2×10^-10 kb(NH3) = 1.6×10^-5 # Solution -

To calculate pKa - pKa = -log(Ka)