Calculate the ph of 0.02 M Hcl
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Since HCl is a strong acid it completely dissociates.
Therefore all the H+ protonates water molecules to give H3O+.
Its concentration here is high enough to ignore H3O+ contribution from water so the pH is just -log(0.02) = 1.7. pH + pOH = 14 so the pOH is 12.3.
The pH is -Log[H+] for HCl - being a strong acid.
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