Chemistry, asked by zoyaanis2002, 4 months ago

calculate the ph of 0.02 M sulfuric acid​

Answers

Answered by TrustedAnswerer19
8

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 H_2SO_4\:\longrightarrow\:2H^+\:+\:(SO_4)^2-\\\\[H^+]\:=\:2×0.02\:=\:0.04\: M

P^H\:=\:-\:log\:[H^+]\\=\:-\:log(0.04)\\\:\:\:\:=\:1.4

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Answered by mazhigariya
1

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