Question

Calculate the pH of 0.025M h3po3

Answer 1

Answer:

H

2

SO

4

is a strong diprotic acid. The equation for ionization is

H

2

SO

4

→2H

+

+SO

4

2

−

Each molecule of acid gives 2 molecules of H

+

.

The concentration of H

+

ion is 2 x 0.005 = 0.010M

pH=−log[H

+

]=−log[0.01]=2.

pH=2

Answer is option C.

Answer 2

Answer:

1.125

Explanation:

Eq. For ioniazion is

H3PO3 = 3H+ + PO3 3-

Concentration of H+ ion is 0.025 × 3 = 0.075M

pH = - log(H+) = - log(0.075) = 1.125

Italics = uppercase