calculate the PH of 0.050m H2SO4 solution
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Answer:
Explanation:
pH = - log(C)
= - log 0.05
= - log ( 5 × 10⁻²)
= - log 5 - log 10⁻²
= - 0.699 - (-2)
= - 0.699 + 2
= 1.3
∴ the pH of H₂SO₄ is 1.3
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