Question

calculate the pH of 0.05M BaoH2 solution.​

Answer 1

Answer:

13

Explanation:Ba(OH)2 ⟶Ba  +2  +2OH  −

∴[OH  −  ]=0.05×2=0.10M

⇒pOH=−log(0.10)=1

As we know that,

pH+pOH=14

∴pH=14−pOH=14−1=13