Calculate the pH of 0.05m of KOH solution
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Explanation: hope that answer is correct!!!
KOH + H2O → H3O+ + KO
(0.05)
pOH = -log 10[OH-]
= - log10 [0.05]
= - log10 5.0 + [-log10 10-²]
= - 0.6990 +2
pOH = 1.301
→ pH +pOH = 14
pH = 14 - 1.301
= 12.699
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