Question

calculate the pH of
0.05M Solution of NH4Cl​

Answer 1

Answer:

For salt of weak base, strong acid like NH

3

Cl,

K

h

=

K

b

K

w

=

1.8×10

−5

10

−14

=5.56×10

−10

pH=7−

2

1

[pK

b

+logC]=7−

2

1

{[−log(1.8×10

−5

)]+log0.05}=pH=5.28