Calculate the pH of 0.1 M hcl solution
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As hcl dissociates completely
N = 0.1
[H+] = 0.1 = 10^-1
ph = -log[H+] = -log10^-1 = 1
So, ph of 0.1m h hcl l will be 1
N = 0.1
[H+] = 0.1 = 10^-1
ph = -log[H+] = -log10^-1 = 1
So, ph of 0.1m h hcl l will be 1
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