Calculate the ph of 0.1 m solution of nh4oh
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Answer:
the pH of solution is 3
explanation and Solution:
first of all, we will convert 0.1 into exponential form
= 1 x 10⁻¹
pH = -Log [H+]
= -Log [ 1 x 10⁻³]
= -[log 1 + log 10⁻³]
= - [0 + (-3)]
= -[0-3]
= -[-3]
= 3
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