Question

calculate the PH of 0.1m NaOH solition​

Answer 1

Answer:

pH = 13

Explanation:

Alternatively we can calculate

pOH = - log [OH-]

         = - log [10-1] = 1

And remembering that,

         pH + pOH = 14

we get,

    pH = 14 - 1

     pH= 13.

Answer 2

Answer:

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Explanation:

NaOH is a strong electrolyte. It completely dissociates in aqueous solution.

NaOH→Na++OH−

Hence, [OH−]=[NaOH]=0.1M

pOH=−log [OH−]

pOH=−log 0.1

pOH=1

Now,

pH=14−pOH

pH=14−1

pH=13

Hence, the pH of 0.1 M NaOH is 13.