calculate the pH of 0.4g of NaOH dissolved in water to give 1000 ml of solution.
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The number of moles in 1000ml
Moles = mass / molar mass
Molar mass of NaOH = 23 + 16 + 1 = 40g /mol
Moles = 0.4/40 = 0.01 moles
0.01 moles in 1000 ml is the molarity.
0.01 M
Ph = - log 0.01
PH = - (-2) = 2
The pH is 2
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