Question

Calculate the pH of 1×10^-8m of hcl

Answer 1

Given concentration of H+ ion is
:- 1 × 10 ^ ( - 8 )m

pH = -log ( H+ )

= - log ( 1 × 10 ^ ( - 8 )

= - ( - 8 ) log10

= 8 × 1

= 8

value of log 10 = 1

and log a^x = x loga


pH is 8

Answer 2

${10}^{ - 8} con \: hcl \: is \: possible \: only \: when \\ it \: is \: diluted \: with \: \: water. \\ so \: (h + )con \: = \frac{ {10}^{ - 8} + {10}^{ - 7} }{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 0.55 \times {10}^{ - 7} \\ so \: \: ph = - log(0.55 \times {10}^{ - 7} ) \\ \: \: \: \: \: \: \: \: \: \: \: \: = - log(0.55) + 7 \\ \: \: \: \: \: \: \: \: \: \: \: \: = - 0.2596 + 7 = 6.74$
I hope it help's