Question

calculate the ph of 10-4 mol/dm 3 of Ba(OH)2​

Answer 1

Answer

here Ba(oh)2 is strong  base so, concentration of (oh) is equal to concentration of Ba(OH)2

poh= --log[OH^-]

And here concentration of OH^-1 is 10^-4

therefore P0h = 4 log10

here log 10 = 1

therefore Poh = 4*1 = 4

Now poh+ph=14

thus using above relation ph=10

i hope it helps you..........