Calculate the ph of 10^-8 m hcl solution taking into account the h+ produced by water also
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Answer:
The pH of 10⁻⁸ HCl solution taking into account the h+ produced by water will be 6.98.
Explanation:
10⁻⁸ HCl will dissociates to give 10⁻⁸ H⁺ ions
Similarly water will dissociates to give equal concentration of H⁺ and OH⁻ ions
H₂O = H⁺ + OH⁻
[H⁺] = [OH⁻] = x lets say
Hence in the solution, net concentration of H⁺ ions will be (x + 10⁻⁸)
=> (x + 10⁻⁸)(x) = 10⁻¹⁴
=> x² + 10⁻⁸x - 10⁻¹⁴ = 0
=> x = 9.5 x 10⁻⁸
So,
[H⁺] = (x + 10⁻⁸) = 9.5 x 10⁻⁸ + 10⁻⁸ = 10.5 x 10⁻⁸
=> pH = -log[H⁺]
= -log[10.5 x 10⁻⁸]
= 6.98
Hence the pH of 10⁻⁸ HCl solution taking into account the h+ produced by water will be 6.98.
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