Calculate the pH of a 0.033 M ammonia solution. If 0.033 M NH4Cl is introduced in this solution at the same temperature. (Kb for NH3 = 1.77 x 10-5)
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I know itS answer
According to this equation,
pOH = pKb + log
where, pKb is to be calculated from Kb.
Kb for NH3 = 1.7710-5
pKb = -log Kb = -log (1.7710-5) = 4.75
[Salt] = [NH4Cl] = 0.033 M
[Base] = [NH3] = 0.033 M
When we put all these values in the equation,
pOH = 4.75 + log
= 4.75 + log (1) = 4.75+0 = 4.75
pOH = 4.75
pH = 14 - 4.75 = 9.25
pH = 9.25
pH of the solution = 9.25
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To calculate the pH of the solution containing ammonia and NH4Cl, we will use the Handerson Hasselbach equation.
According to this equation,
pOH = pKb + log
where, pKb is to be calculated from Kb.
Kb for NH3 = 1.7710-5
pKb = -log Kb = -log (1.7710-5) = 4.75
[Salt] = [NH4Cl] = 0.033 M
[Base] = [NH3] = 0.033 M
When we put all these values in the equation,
pOH = 4.75 + log
= 4.75 + log (1) = 4.75+0 = 4.75
pOH = 4.75
pH = 14 - 4.75 = 9.25
pH = 9.25
pH of the solution = 9.25
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