Question

Calculate the pH of:
a) 1.00 x 10-3 mol dm-3 ethanoic acid solution, CH3COOH(aq). Ka
(CH3COOH) = 1.8 x 10-5 at 298 K.

Answer 1

Answer:

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Answer 2

Answer:

Ka=Cx^2/1-x

Ka =1.8 x 10^-5

C = 0.1

If we consider x is negligible ie., x~0

Then x=(Ka/c)^0.5

={1.8 x 10^-5/0.1)^0.5 =0.01342

So concetration of H+ ion =Cx

=0.1 x 0.01342 =0.001342

pH=- log(0.001342) =2.87