Question

Calculate the pH of a 2x 10^-5 M aqueous solution of phenol at 25°C Ka = 1.30 x 10^-10 Kw=1.008 X 10^-14.​

Answer 1

Answer:

Explanation:

Answer:3.6

Explanation:

pKb=-log[1.81x10^-5]

=4.742

pKw=-log[1.008x10^-14]

=13.996

pH=1/2(pKw-pKb-log C)

pH=1/2(13.996-4.742-log(0.01))

pH=1/2(13.996-4.742-2)

pH=1/2(7.254)

pH=3.627

pH=3.6

Answer 2

Answer:6.95

Explanation:This is an example of calculating the pH of dilute solution of a very weak acid and to calculate it we must be very careful