calculate the pH of a solution made by mixing 50 ml of 0.01M Na(OH)2 with 50 ml water
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Answer:
pH=11.6
Explanation:
Firstly,
molarity of NaOH given=0.01M
so no of moles in 50 ml of naoh is =0.0005
now the same no of moles of NaOH wil be present when we add 50ml of water.
so the new molarity will be 0.005.
so pOH= -log(0.005)=2.3
so pH=14-pOH = 11.6
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