Question

Calculate the pH of a solution obtained by dissolving 490 mg H2SO4 in water so that the total volume of solution becomes 100 ml . ( please explain the derivation)

Answer 1

Molecular mass of H2 SO4 Sulfuric acid = 98
Num of moles = 0.490 /98 = 0.005
Volume of solution = 0.100 L

Molarity = 0.005/0.100 = 0.050 M

There are 2 ions of H+ for each molecule of the acid. So
[ H⁺ ] = 0.100 M

pH = - Log₁₀ [ H⁺ ] = 1

Answer 2

Answer:

pH =1

Explanation:

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