calculate the pH of a solution obtained by mixing 50ml of 0.2 M HCL with 49.9ml of 0.2 M NAOH solution
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Explanation:
NaOH+HCl→NaCl+H
2
O
1 mole 1 mole
(For HCl and NaOH normality = molarity)
M
f
=
V
1
+V
2
n
1
N
1
V
1
−
n
2
N
2
V
2
50+50
1
50×0.4
−
1
50×0.2
=
100
20−10
=
10
1
or 10
−1
M
[H
+
]=10
−1
M;
pH=−log(10
−1
)
pH=1
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