Question

Calculate the pH of acid with Ka = 10^-6 and 0.01 M
0
4
6
2
??
Give detailed answer pls

Answer 1

Answer:

PH=8

Explanation:

PH=1/2 [PKa-log(acid)]

PH=1/2 [6-log(0.01)]

PH=1/2(6-(-2))=1/2(8)=4

Therefore,PH=8.