Calculate the PH of and POH of 1.00 × 10-3 M solution of Acetic Acid.
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Answer:
PH=3
POH = 11
Explanation:
[H+] = 1×10^-3M
PH= - log[H+]
= - log[1×10^-3]
= 3
Now, PH + POH = 14
So, POH = 11
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