calculate the pH of solutions fromed by mixing 400 ml hcl with 100 ml of 4.5 naoh
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Explanation:
The pH of the solution should be = 12.
According to the given question HCL+NaOH+NaCL+H2O
As per details that are given in the question we can calculate the following
No. Of moles of HCL= (40ml) (.1mol/L)
= (0.04L) (0.1mol/L) = 0.004 moles
No. Of moles of NaOH = (10ml) (.45moles/L)
= (0.01L) (0.45mol/L) = 0.0045 moles
Therefor, excess amount of NaOH will be = 0.0045moles - 0.004moles = 0.0005 moles
Therefor the total volume will be
= 0.04 + 0.01 = 0.05L
Molarity of OH will be = 0.0005moles/0.05L= 0.01M
pOH = -log (OH)
= - log 0.01
Therefor pOH = 2
So pH = 14 - pOH
14 - 2 = 12
Thus, pH of above solution is = 12
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