Chemistry, asked by Technicalworld, 11 months ago

calculate the ph of the following - 8.3 × 10^-3 M of HCl

Answers

Answered by harsharora111

0

Answer:

Given

[H+] = 8.3 × 10^-3

pH = 3- log8.3

pH = 3- .91

pH = 2.09

Thanks for Reading

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