Calculate the ph of the solution formed by mixing equal volume of two solution of a and b of have strong acid having ph equal to 6 and ph is equal to 4 respectively
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>>ph of solution a=6
>>>[H+] = 10^-6 mol L^-1
>>>ph of solution b = 4
>>>[H+] = 10^-4 mol L^-1
>>>[H+] = 10^-6 +10^-4 / 2 mol L^-1.
>>[H+] = 5.05 ×10^-5 mol L^-1.
>>ph = - log [H+]
>>ph = - log(5.0 ×10^-5) =4.3
>>>[H+] = 10^-6 mol L^-1
>>>ph of solution b = 4
>>>[H+] = 10^-4 mol L^-1
>>>[H+] = 10^-6 +10^-4 / 2 mol L^-1.
>>[H+] = 5.05 ×10^-5 mol L^-1.
>>ph = - log [H+]
>>ph = - log(5.0 ×10^-5) =4.3
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