Question

Calculate the ph of the solution formed by mixing equal volume of two solution of a and b of have strong acid having ph equal to 6 and ph is equal to 4 respectively

Answer 1

>>ph of solution a=6



>>>[H+] = 10^-6 mol L^-1



>>>ph of solution b = 4



>>>[H+] = 10^-4 mol L^-1


>>>[H+] = 10^-6 +10^-4 / 2 mol L^-1.



>>[H+] = 5.05 ×10^-5 mol L^-1.



>>ph = - log [H+]



>>ph = - log(5.0 ×10^-5) =4.3