Question

calculate the pH of3.8×10^-3MHcl​

Answer 1

Answer:There are two ways you can do this. The easy way is to realize that HCl is a strong acid, so its dissociation is considered complete, and [HCl]=[H+].

EASY WAY

Recall:

   pH=−log[H+]

From the knowledge that pH=−log[H+]=−log[HCl], we can say:

   pH=−log(3.1×10−3M)=2.508638306

   =2.51