calculate the pH value of 0.005 M NaOH.2
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NaOH.2 is not base
pH of NaOH
Here, the molarity of the solution is 0.05M.
That means,every 1 litre solution has 0.05 M NaOH in it.
Further, the dissociation is practically 100%.
=> pH = 14 - pOH = 14 - 1.30102999566 = 12.699 (approx.)
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