Calculate the ph value of 1.0 x10^-8 m hcl
Answers
Answered by
0
Answer:
THE PH OF THIS HCL SOLUTION IS QUITE SOUR AND PH TURNS INTO LIGHT ORANGE COLOUR
Answered by
0
Answer:
Explanation:
[H+] total =[H+] acid +[H+] water
Since, HCl is a strong acid and is completely ionized
[H
+
]HCl=1.0×10
−8
The concentration of H+ from ionization is equal to the [OH
–
] from water,
[H
+
]H
2
O=[OH
–
]H
2
O
=x (say)
[H
+
]total=1.0×10
−8
+x
But
[H
+
][OH
–
]=1.0×10
−14
(1.0×10
−8
+x)(x)=1.0×10
−14
X
2
+10
−8
x–10
−14
=0
Solving for x, we get x=9.5×10
−8
Therefore,
[H
+
]=1.0×10
−8
+9.5×10
−8
=10.5×10
−8
=1.05×10
−7
pH=–log[H
+
]=–log(1.05×10
−7
)=6.98
Hence, this is the answer.
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