Question

Calculate the pH value of a solution obtained by mixing 20 ml of 0.3M HNO3 and 20ml of 0.1M of koh

Answer 1

HEY GUYS


According to the law of dillution:

N1V1-N2V2=NV

$0.3 \times 20 - 0.1 \times 20 = 6 - 2 = 4$
4=N{V1+V1}
4=N×(20+20)
N=0.1
AS WE KNOW THIS IS CONCENTRATION OF OH IONS
$p(oh) = - log(oh)$
$p(oh)= - log( {10}^{ - 1} ) = 1$
Also p(OH) +p(H)=14

$p(h) = 14 - 1 = 13$

HOPE IT HELPS