Question

Calculate the phone of 0.0008M Ba(oH) 2 solution

Answer 1

Answer:

When Ba(OH)2 dissolves it produces 2 OH- ions per mole of Ba(OH)2. Therefore the concentration of OH- ions will be 0.08 x 2 = 0.16 moles/L

First find the pOH of the solution. pOH = 10^-0.16 0.692

The pH therefore, is 14 - pOH

14 - 0.692 = 13.3

Answer 2

Answer:

poshan kise kahate Hain yah kitne prakar ka hota Hai