Question

calculate the pOH and pH of KOH whose concentration is 0.01M​

Answer 1

Answer:

pH=2

pOH = 12

Formulae

pH= -log[H+]

14 -pH = pOH

Solution:

0.01 -> scientific notation = 1×10^-2

= -log[1×10^-2]

= -[log1 + log 10^-2]

= -[0+(-2)}

= -[0-2]

= 0+2

pH= 2

pOH = 14 - 2

= 12