Chemistry, asked by rushi474, 15 days ago

Calculate the POH of 0.005M HCL solution
.

Answers

Answered by Anonymous

0

Answer:

HCl is a strong acid that dissociates completely:

HCl(aq) → H+(aq) + Cl-(aq)

[H+] = [HCl] = 0.005M

pH = -log [H+]

pH = - log 0.005

pH = 2.3

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