calculate the poH of 0.007 M aqueous solution of NaOH.(log 7=0.8451)
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Answer:
The answer is 2.1549
Explanation:
The concentration of hydroxal ions is [OH-] = 0.007
Formula to calculate pH:
pH + pOH = 14
pOH = - log[OH-]
= - log [0.007]
= - log [7 x 10 ^3]
= - (log7 - 3log 10)
= 3 log10 - log 7 (log 10 = 1)
= 3 x1 - 0.8451 = 3 - 0.8451
pOH = 2.1549
Hence the value of pOH is 2.1549. Now put in the above equation to calculate pH.
pH + pOH = 14
pH = 14 - pOH
pH = 14 - 2.1549 = 11. 8451
pH = 11.84
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