Question

calculate the POH OF 0.03 M Hcl
Solution

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Answer 1

Explanation:

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Answer 2

Question-

Calculate the pH OF 0.03 M HCl?

Answer-

pH OF 0.03 M HCl is

$pH= -log[H+]$

$0.03N=HCl$

$[H+]=3×10^-2$

$pH=-log[3×10^-2]$

$2log3$

➡$1.52$